Lecture 28:- Count Digits

To count the number of digits in a given integer in Java, you can use a simple loop and divide the number by 10 iteratively until the quotient becomes zero. The count of divisions will give you the number of digits. Here's a Java program to count the digits in a given integer:

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import java.util.Scanner; public class CountDigits {    public static void main(String[] args) {        Scanner scanner = new Scanner(System.in);        System.out.print("Enter an integer: ");        int number = scanner.nextInt();        // Calculate the number of digits        int count = 0;        int tempNumber = Math.abs(number); // Use Math.abs() to handle negative numbers        while (tempNumber != 0) {            tempNumber /= 10;            count++;        }        System.out.println("Number of digits: " + count);        scanner.close();    } }

Example output:

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Enter an integer: 123456 Number of digits: 6

In the program above, we take the user input for the integer and store it in the variable number. We then initialize a variable count to 0 to keep track of the number of digits. To handle negative numbers, we use Math.abs() to get the absolute value of the input number (tempNumber).

The while loop continues to divide tempNumber by 10 until tempNumber becomes 0. During each iteration, the number of digits is incremented by 1. Finally, the program prints the count of digits.

Keep in mind that the approach mentioned above works for non-negative integers. If you need to handle negative integers differently, you can adjust the logic accordingly.