Lecture 71:- Let's Code nCr using Recursion

Certainly! Here's an example implementation of calculating nCr using recursion in Python:

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def nCr(n, r):    # Base cases    if r == 0 or r == n:        return 1    # Recursive case    return nCr(n - 1, r - 1) + nCr(n - 1, r)

Let's break down how the code works:

1. The nCr function takes two parameters: n (the total number of items) and r (the number of items to choose).
2. We define the base cases: if r is 0 or r is equal to n, then it means either we have to choose 0 items or we have to choose all the items. In both cases, there is only one way to do so, and we return 1.
3. In the recursive case, we use the formula for combinations: nCr = (n-1)Cr-1 + (n-1)Cr. We make two recursive calls to calculate the combinations for choosing r-1 items from n-1 items and choosing r items from n-1 items.
4. We add the results of the recursive calls and return the sum, which represents the total number of combinations (nCr).

Here's an example usage of the nCr function:

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result = nCr(5, 2) print(result)  # Output: 10 result = nCr(6, 3) print(result)  # Output: 20

In the first example, we calculate the number of combinations for choosing 2 items out of 5 items, which is 10.

In the second example, we calculate the number of combinations for choosing 3 items out of 6 items, which is 20.