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Certainly! Here's an example of nested recursion in C++, where a function calls itself with the result of its own recursive call as an argument:
cppCopy code
#include <iostream>
int nestedRecursion(int n) {
if (n > 100) {
return n - 10;
} else {
return nestedRecursion(nestedRecursion(n + 11));
}
}
int main() {
int result = nestedRecursion(95);
std::cout << result << std::endl; // Output: 91
return 0;
}
In this example, the nestedRecursion
function takes an integer n
as input. If n
is greater than 100, it subtracts 10 and returns the result. Otherwise, it calls itself twice with n + 11
as an argument.
The nested recursive calls create a recursive "tree" structure, similar to the Python example. The recursion continues until n
becomes greater than 100, and then the intermediate results are unwound and propagated back up the recursion.
When the code is executed, it will output 91
, which is the final result of the nested recursion.
Nested recursion can be useful in solving certain problems that require complex dependencies between recursive calls and multiple levels of recursion. However, it's crucial to define proper termination conditions to prevent infinite recursion.
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