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It sounds like you want to merge nodes between zeros in a linked list. Here's how you can approach this problem:
- Traverse the linked list and keep track of the current sequence of non-zero nodes.
- When you encounter a zero node, merge the current sequence of non-zero nodes into a single node (e.g., by summing their values) and update the pointers accordingly.
- Continue traversing the linked list and repeating this process until you reach the end.
Here's a C++ implementation of merging nodes between zeros in a linked list:
cppCopy code
#include <iostream> class Node { public: int data; Node* next; Node(int value) : data(value), next(nullptr) {} }; Node* mergeNodesBetweenZeros(Node* head) { Node* current = head; Node* prev = nullptr; int sum = 0; while (current) { if (current->data == 0) { if (prev) { prev->data = sum; prev->next = current->next; sum = 0; } else { head = current->next; } } else { sum += current->data; } prev = current; current = current->next; } return head; } void displayList(Node* head) { while (head) { std::cout << head->data << " "; head = head->next; } std::cout << std::endl; } int main() { Node* head = new Node(1); head->next = new Node(2); head->next->next = new Node(0); head->next->next->next = new Node(3); head->next->next->next->next = new Node(0); head->next->next->next->next->next = new Node(4); std::cout << "Original List: "; displayList(head); head = mergeNodesBetweenZeros(head); std::cout << "List after merging nodes between zeros: "; displayList(head); return 0; }
In this example, the
mergeNodesBetweenZeros
function merges nodes between zeros in the linked list. ThedisplayList
function is used to display the original and modified lists.Keep in mind that this implementation assumes that there are no consecutive zeros. If consecutive zeros are allowed, you might need to adjust the algorithm accordingly.
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